Provide Oracle 1z1-071 Practice Test Engine for Preparation [Q165-Q190]

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Provide Oracle 1z1-071 Practice Test Engine for Preparation

Detailed New 1z1-071 Exam Questions for Concept Clearance


Oracle 1z0-071 exam covers a broad range of topics related to SQL development and database management, including SQL queries, data manipulation, data control language, data definition language, transactions, and database security. Candidates must demonstrate their ability to write complex SQL queries, manage database objects, and perform database administration tasks. 1z1-071 exam is challenging, but passing it can open up many opportunities for IT professionals in various industries.


Oracle 1z1-071 Exam, also known as the Oracle Database SQL Exam, is a certification exam that tests candidates on their knowledge of SQL (Structured Query Language) and the Oracle Database. 1z1-071 exam is designed for database professionals who are seeking to validate their expertise in SQL and database management. The Oracle 1z1-071 Exam is a popular certification that is recognized globally and is a requirement for some job roles in the IT industry.


To pass the Oracle 1z0-071 certification exam, you need to have a good understanding of SQL and its syntax. You should also be familiar with database concepts such as data modeling, normalization, and indexing. In addition, you need to have hands-on experience with Oracle Database SQL to be able to answer the exam questions effectively.

 

NEW QUESTION # 165
Which statements are true? (Choose all that apply.)

  • A. The data dictionary is created and maintained by the database administrator.
  • B. Both USER_OBJECTS and CAT views provide the same information about all the objects that are owned by the user.
  • C. Views with the same name but different prefixes, such as DBA, ALL and USER, use the same base tables from the data dictionary
  • D. The USER_CONS_COLUMNS view should be queried to find the names of the columns to which a constraint applies.
  • E. The usernames of all the users including the database administrators are stored in the data dictionary.
  • F. The data dictionary views can consist of joins of dictionary base tables and user-defined tables.

Answer: C,D,E


NEW QUESTION # 166
Which two are true about queries using set operators such as UNION?

  • A. Queries using set operators do not perform implicit conversion across data type groups (e.g. character, numeric)
  • B. In a query containing multiple set operators INTERSECT always takes precedence over UNION and UNION ALL
  • C. An expression in the first SELECT list must have a column alias for the expression
  • D. All set operators are valid on columns all data types.
  • E. CHAR columns of different lengths used with a set operator retum a vAacsua mhtoe e equals the longest CHAR value.

Answer: B,E

Explanation:
Set operators allow you to combine multiple queries into a single query. The key points for each option are:
A). An expression in the first SELECT list does not need to have a column alias; however, the column alias given to an expression in the first SELECT list is used as the column name of the output.
B). This statement is true. When CHAR columns of different lengths are combined with a set operator, Oracle will pad the shorter values with spaces to match the length of the longest value. This behavior is consistent with the SQL standard and Oracle's treatment of the CHAR datatype.
C). Oracle Database performs implicit conversion between compatible data types where necessary when using set operators. For example, a NUMBER can be implicitly converted to a VARCHAR2 and vice versa if the context requires it.
D). This is true. When multiple set operators are used in a single query, the INTERSECT operator takes precedence over the UNION and UNION ALL operators. This order of operation can be overridden by using parentheses.
E). Not all set operators work with all data types. For instance, LOB and LONG RAW data types cannot be used with set operators.
References:
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "Set Operators"
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "Data Types"


NEW QUESTION # 167
Evaluate the following statement.

Which statement is true regarding the evaluation of rows returned by the subquery in the INSERTstatement?

  • A. The insert statement would give an error because the ELSEclause is not present for support in case none of WHENclauses are true.
  • B. They are evaluated by the first WHENclause. If the condition is false, then the row would be evaluated by the subsequent WHENclauses.
  • C. They are evaluated by the first WHENclause. If the condition is true, then the row would be evaluated by the subsequent WHENclauses.
  • D. They are evaluated by all the three WHENclauses regardless of the results of the evaluation of any other WHENclause.

Answer: D

Explanation:
Explanation/Reference:
References:
http://psoug.org/definition/WHEN.htm


NEW QUESTION # 168
View the exhibit and examine the structure in ORDERS and ORDER_ITEMS tables.

You need to create a view that displays the ORDER_ID, ORDER_DATE, and the total number of items in each order.
Which CREATE VIEW statement would create the view successfully?

  • A. CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
    COUNT(i.line_item_id)||'NO OF ITEMS'FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_dateWHITH CHECK OPTION;
  • B. CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
    COUNT(i.line_item_id)FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_date;
  • C. CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
    COUNT(i.line_item_id)"NO OF ITEMS"FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_date;
  • D. CREATE OR REPLACE VIEW ord_vu (order_id, order_date)AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)"NO OF ITEMS"FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id, o.order_date;

Answer: C


NEW QUESTION # 169
Which is the default column or columns for sorting output from compound queries using SET operators such as INTERSECT in a SQL statement?

  • A. The first column in the first SELECT of the compound query
  • B. The first NUMBER column in the first SELECT of the compound query
  • C. The first NUMBER or VARCHAR2 column in the last SELECTof the compound query
  • D. The first column in the last SELECT of the compound query
  • E. The first VARCHAR2 column in the first SELECT of the compound query

Answer: A


NEW QUESTION # 170
No-user-defined locks are used in your database.
Which three are true about Transaction Control Language (TCL)?

  • A. ROLLBACKwithout the TO SAVEPOINT clause undoes all the transaction's changes, releases its locks and erases its savepoints.
  • B. ROLLBACKwithout the TO SAVEPOINT clause undoes all the transaction's changes but does not erase its savepoints.
  • C. COMMITerases all the transaction's savepoints and releases its locks.
  • D. ROLLBACK TO SAVEPOINT undoes the transaction's changes made since the named savepoint and then ends the transaction.
  • E. COMMITends the transaction and makes all its changes permanent.
  • F. ROLLBACKwithout the TO SAVEPOINT clause undoes all the transaction's changes but does not release its locks.

Answer: A,C,E

Explanation:
Explanation/Reference: https://docs.oracle.com/cd/A58617_01/server.804/a58233/trans.htm
https://docs.oracle.com/cd/B19306_01/server.102/b14200/statements_9021.htm


NEW QUESTION # 171
Examine the structure of the SALES table. (Choose two.)
Examine this statement:
SQL > CREATE TABLE sales1 (prod_id, cust_id, quantity_sold, price)
AS
SELECT product_id, customer_id, quantity_sold, price
FROM sales
WHERE 1 = 2;
Which two statements are true about the SALES1 table?

  • A. It will not be created because of the invalid WHERE clause.
  • B. It will have NOT NULL constraints on the selected columns which had those constraints in the SALES table.
  • C. It is created with no rows.
  • D. It has PRIMARY KEY and UNIQUE constraints on the selected columns which had those constraints in the SALES table.
  • E. It will not be created because the column-specified names in the SELECT and CREATE TABLE clauses do not match.

Answer: B,C


NEW QUESTION # 172
Examine the structure of the MEMBERS table:

Examine the SQL statement:
SQL > SELECT city, last_name LNAME FROM MEMBERS ORDER BY 1, LNAME DESC; What would be the result execution? (Choose the best answer.)

  • A. It displays all cities in ascending order, within which the last names are further sorted in descending order.
  • B. It fails because a column alias cannot be used in the ORDER BY clause.
  • C. It fails because a column number and a column alias cannot be used together in the ORDER BY clause.
  • D. It displays all cities in descending order, within which the last names are further sorted in descending order.

Answer: A


NEW QUESTION # 173
MANAGER is an existing role with no privileges or roles.
EMP is an existing role containing the CREATE TABLE privilege.
EMPLOYEES is an existing table in the HR schema.
Which two commands execute successfully?

  • A. GRANT CREATE TABLE, SELECT ON hr. employees TO manager;
  • B. GRANT CREATE SEQUENCE TO manager, emp;
  • C. GRANT SELECT, INSERT ON hr.employees TO manager WITH GRANT OPTION:
  • D. GRANT CREATE ANY SESSION, CREATE ANY TABLE TO manager;
  • E. GRANT CREATE TABLE, emp TO manager;

Answer: B,D

Explanation:
In Oracle SQL, roles can be granted privileges and other roles, and these privileges can then be passed on to users.
* Statement A is correct: GRANT CREATE SEQUENCE TO manager, emp; successfully grants the CREATE SEQUENCE privilege to both the manager and emp roles.
* Statement E is correct: GRANT CREATE ANY SESSION, CREATE ANY TABLE TO manager; successfully grants two system privileges to the manager role.
* Statements B, C, and D are incorrect for the following reasons:
* B is incorrect because the correct syntax to grant object privileges includes separating privileges with commas, not spaces, and the object name should be in singular form (hr.employees).
* C is incorrect because you cannot grant a role and a privilege in the same statement.
* D is incorrect because the correct syntax for granting object privileges does not include the privilege CREATE TABLE before specifying the object (hr.employees).


NEW QUESTION # 174
Examine the description of the PRODUCT_STATUS table:

The STATUS column contains the values 'IN STOCK' or 'OUT OF STOCK' for each row.
Which two queries will execute successfully?

  • A. Option D
  • B. Option A
  • C. Option F
  • D. Option C
  • E. Option E
  • F. Option B

Answer: E,F


NEW QUESTION # 175
Which three statements are true about defining relations between tables in a relational database?

  • A. Primary key columns allow null values.
  • B. Every foreign key value must refer to a matching primary or unique key value.
  • C. Unique key columns allow null values.
  • D. Foreign key columns allow null values.
  • E. Every primary or unique key value must refer to a matching foreign key value.

Answer: A,B


NEW QUESTION # 176
View the Exhibit and examine the data in the PRODUCT_INFORMATION table.

Which two tasks would require subqueries? (Choose two.)

  • A. displaying the number of products whose list prices are more than the average list price
  • B. displaying all the products whose minimum list prices are more than average list price of products having the status orderable
  • C. displaying the minimum list price for each product status
  • D. displaying the total number of products supplied by supplier 102071 and having product status OBSOLETE
  • E. displaying all supplier IDs whose average list price is more than 500

Answer: A,B


NEW QUESTION # 177
Which two statements are true regarding the COUNT function? (Choose two.)

  • A. It can only be used for NUMBER data types.
  • B. A SELECT statement using the COUNT function with a DISTINCT keyword cannot have a WHERE clause.
  • C. COUNT(inv_amt) returns the number of rows in a table including rows with NULL in the INV_AMT column.
  • D. COUNT(DISTINCT inv_amt) returns the number of rows excluding rows containing duplicates and NULLs in the INV_AMT column.
  • E. COUNT(*) returns the number of rows including duplicate rows and rows containing NULL value in any column.

Answer: D,E


NEW QUESTION # 178
Examine the data in the CUSTOMERStable:

You want to list all cities that have more than one customer along with the customer details.
Evaluate the following query:

Which two JOIN options can be used in the blank in the above query to give the correct output? (Choose two.) LEFT OUTER JOIN

  • A. NATURAL JOIN
  • B. JOIN
  • C. LEFT OUTER JOIN
  • D. RIGHT OUTER JOIN
  • E. FULL OUTER JOIN

Answer: B,D


NEW QUESTION # 179
You want to display 5 percent of the rows from the sales table for products with the lowestAMOUNT_SOLD and also want to include the rows that have the sameAMOUNT_SOLDeven if this causes the output to exceed 5 percent of the rows.
Which query willprovide the required result?

  • A. SELECT prod_id, cust_id, amount_sold FROM sales ORDER BY amount_sold FETCH FIRST 5 PERCENT ROWS WITH TIES;
  • B. SELECT prod_id, cust_id, amount_sold FROM sales ORDER BY amount__sold FETCH FIRST 5 PERCENT ROWS ONLY;
  • C. SELECT prod_id, cust_id, amount_sold FROM sales ORDER BY amount_sold FETCH FIRST 5 PERCENT ROWS ONLY WITH TIES;
  • D. SELECT prod_ id, cust_id, amount_sold FROM sales ORDER BY araount_sold FETCH FIRST 5 PERCENT ROWS WITH TIES ONLY;

Answer: C


NEW QUESTION # 180
Which two queries execute successfully?

  • A. SELECT NULLIF (100) FROM DUAL;
  • B. SELECT COALESCE(100, NULL, 200) FROM DUAL;
  • C. SELECT NULLIF (100, 'A') FROM DUAL;
  • D. SELECT NULLIF(NULL, 100) FROM DUAL;
  • E. SELKCT COALESCE (100, 'A') FROM DUAL;

Answer: A,B


NEW QUESTION # 181
Which two statements are true about the ORDER BY clause?

  • A. Numeric values are displayed in descending order if they have decimal positions.
  • B. Only columns that are specified in the SELECT list can be used in the ORDER BY cause.
  • C. NULLS are not included in the sort operation.
  • D. Column aliases can be used In the ORDER BY cause.
  • E. Ina character sort, the values are case-sensitive.

Answer: D,E

Explanation:
The ORDER BY clause in Oracle SQL is used to sort the result set of a query by one or more columns, and it comes with its own set of rules and behaviors:
* D. Column aliases can be used In the ORDER BY clause: True, column aliases that are specified in the SELECT clause can be used in the ORDER BY clause to refer to the columns to sort the results by.
* E. In a character sort, the values are case-sensitive: Oracle sorts results in case-sensitive order by default when using the ORDER BY clause with character columns, unless otherwise specified by the NLS_SORT parameter.
References:
* Oracle Database SQL Language Reference 12c, which provides details on sorting query results using ORDER BY.


NEW QUESTION # 182
View the Exhibit and examine the structure of the PRODUCTS table.

You must display the category with the maximum number of items.
You issue this query:

What is the result?

  • A. It generates an error because = is not valid and should be replaced by the IN operator.
  • B. It executes successfully but does not give the correct output.
  • C. It generate an error because the subquery does not have a GROUP BY clause.
  • D. It executes successfully and gives the correct output.

Answer: C


NEW QUESTION # 183
Which three tasks can be performed using SQL functions built into Oracle Database?

  • A. combining more than two columns or expressions into a single column in the output
  • B. displaying a date in a nondefault format
  • C. finding the number of characters in an expression
  • D. substituting a character string in a text expression with a specified string

Answer: B,C,D


NEW QUESTION # 184
Examine this statement:
SELECT cust_id, cust^last_ndma "Last Name"
FROM customers
WHERE country_id - 10 UNION
SELECT cust_ID_CUST_NO, cust_last_name
PROM customers
WHERE country__id = 30
Identify three order by clauses, any one of which will complete the query successfully.

  • A. ORDER BY "Last Name
  • B. ORDER BY 2. cust _id
  • C. ORDER BY "CUST^NO
  • D. ORDER BY CUST_NO
  • E. ORDER BY 2,

Answer: A,B,E


NEW QUESTION # 185
Examine the structure of the SALES table.

Examine this statement:

Which two statements are true about the SALES1 table? (Choose two.)

  • A. It will not be created because of the invalid WHERE clause.
  • B. It will have NOT NULL constraints on the selected columns which had those constraints in the SALES table.
  • C. It is created with no rows.
  • D. It has PRIMARY KEY and UNIQUE constraints on the selected columns which had those constraints in the SALES table.
  • E. It will not be created because the column-specified names in the SELECT and CREATE TABLE clauses do not match.

Answer: B,C


NEW QUESTION # 186
In your session, the NLS._DAE_FORMAT is DD- MM- YYYY.There are 86400 seconds in a day.Examine
this result:
DATE
02-JAN-2020
Which statement returns this?

  • A. SELECT TO_ CHAR(TO_ DATE('29-10-2019') +INTERVAL '2'; MONTH + INTERVAL '5'; DAY -
    INTERVAL '86410' SECOND, ' DD-MON-YYYY') AS "date"
    FROM DUAL;
  • B. SELECT TO_ CHAR(TO_ DATE('29-10-2019') + INTERVAL '3' MONTH + INTERVAL '7' DAY -
    INTERVAL '360' SECOND, ' DD-MON-YYYY') AS "date"
    FROM DUAL;
  • C. SELECT-TO_CHAR(TO _DATE('29-10-2019'+ INTERVAL '2' MONTH+INTERVAL '6' DAYINTERVAL
    '120' SECOND, 'DD-MON-YY') AS "daTe"
    FROM DUAL;
  • D. SELECT To CHAR(TO _DATE('29-10-2019') + INTERVAL '2' NONTH + INTERVAL '5' DAY
    INEERVAL '120' SECOND, ' DD-MON-YYY) AS "date"
    FROM DUAL;
  • E. SELECT-TO_CHAR(TO _DATE('29-10-2019'+ INTERVAL '2' MONTH+INTERVAL '4' DAYINTERVAL
    '120' SECOND, 'DD-MON-YY') AS "daTe"
    FROM DUAL;

Answer: D


NEW QUESTION # 187
The first DROP operation is performed on PRODUCTS table using the following command:
DROP TABLE products PURGE;
Then you performed the FLASHBACK operation by using the following command:
FLASHBACK TABLE products TO BEFORE DROP;
Which statement describes the outcome of the FLASHBACK command?

  • A. It recovers only the table structure.
  • B. It is not possible to recover the table structure, data, or the related indexes.
  • C. It recovers the table structure, data, and the indexes.
  • D. It recovers the table structure and data but not the related indexes.

Answer: B

Explanation:
References:
https://docs.oracle.com/cd/B19306_01/server.102/b14200/statements_9003.htm


NEW QUESTION # 188
Which two statements are true regarding the UNION and UNION ALL operators? (Choose two.)

  • A. Duplicates are eliminated automatically by the UNION ALL operator
  • B. The number of columns selected in each SELECT statement must be identical
  • C. NULLS are not ignored during duplicate checking
  • D. The names of columns selected in each SELECT statement must be identical
  • E. The output is sorted by the UNION ALL operator

Answer: B,C


NEW QUESTION # 189
These are the steps for a correlated subquery, listed in random order:
1. The WHEREclause of the outer query is evaluated.
2. A candidate row is fetched from the table specified in the outer query.
3. This is repeated for the subsequent rows of the table, until all the rows are processed.
4. Rows are returned by the inner query, after being evaluated with the value from the candidate row in the outer query.
Which is the correct sequence in which the Oracle server evaluates a correlated subquery?

  • A. 4, 2, 1, 3
  • B. 2, 4, 1, 3
  • C. 2, 1, 4, 3
  • D. 4, 1, 2, 3

Answer: B

Explanation:
Explanation/Reference:
References:
http://rajanimohanty.blogspot.co.uk/2014/01/correlated-subquery.html


NEW QUESTION # 190
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