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How to Study the Oracle 1Z0-071: Oracle Database SQL Exam
The Oracle 1Z0-071 test is prepared in several respects. Different techniques will be established if you intend to take this test. Applicants may consult online different PDFs and also link to online videos to plan for the examination. Various websites provide realistic tests for the planning of the examination. We recommend taking the 1Z0-071 practice exams since offering the Oracle 1Z0-071 test, applicants must take a qualification course or 1Z0-071 dumps that will also help them study for their exam. The Certification Oracle Database SQL (1Z0-071) is designed for Oracle Database candidates from the University of Oracle, IT students who are looking for powerful SQL database expertise, young programmers who are looking for Oracle certification to have their own certification. The exam confirms a candidate’s understanding of Oracle’s SQL and PL/SQL technologies and builds a foundation for potential growth. The Oracle: 1Z0-071 test candidate should have the order, profound understanding of relational database concepts, data limitation and sorting, multi-table exhibition, use of SET operators, managing sightings, objects with a view to a data dictionary, time zones, tables using DML statements, user access controls, aggregate reporting We know that Oracle technologies in large companies are becoming admirable and trendy and are ready to use them to achieve their desired degree of performance. This increases the market level for these certified professionals. For Oracle Cloud credentials, they will be valid for a period of 18 months from the date they were acquired. The new version of the exam should enable the candidates to be recertified to remain current. Over the year, Oracle cloud certifications are continually updated to keep major product and service updates up-to-date. During the time of Oracle Database certification, it needs to be recertified and upgraded to the present version within 12 months.
The Oracle 1Z0-071 is a certification exam that proves the candidate’s knowledge of SQL technology and SQL concepts required to participate in any database project. The target audience for this exam is the IT professionals with some experience in working with these technologies. The fundamental knowledge of general computing concepts and command line interfaces will be an advantage as well.
NEW QUESTION 84
View the Exhibit and examine the structure of ORDER_ITEMS and ORDERS tables.
You need to remove from the ORDER_ITEMS table those rows that have an order status of 0 or 1 in the ORDERS table.
Which two DELETE statements are valid (Choose two.)
- A. DELETEFROM order_itemsWHERE order_id IN (SELECT order_idFROM ordersWHERE orders_status in (0,1));
- B. DELETEFROM (SELECT * FROM order_items I,orders oWHERE i.order_id = o.order_id AND order_status IN (0,1));
- C. DELETE *FROM order_itemsWHERE order_id IN (SELECT order_id)FROM ordersWHERE order_status IN (0,1));
- D. DELETE FROM order_items iWHERE order_id = (SELECT order_id FROM orders oWHERE i.order_id = o.order_id AND order_status IN (0,1));
Answer: A,B
NEW QUESTION 85
You execute the following commands:
SQL > DEFINE hiredate = '01-APR-2011'
SQL >SELECT employee_id, first_name, salary
FROM employees
WHERE hire_date > '&hiredate'
AND manager_id > &mgr_id;
For which substitution variables are you prompted for the input?
- A. only hiredate'
- B. none, because no input required
- C. both the substitution variables ''hiredate' and 'mgr_id'.
- D. only 'mgr_id'
Answer: D
NEW QUESTION 86
Examine the structure of the MEMBERStable:
Name Null? Type
- --------------- ----------------- ---------------------------
MEMBER_ID NOT NULL VARCHAR2 (6)
FIRST_NAME VARCHAR2 (50)
LAST_NAME NOT NULL VARCHAR2 (50)
ADDRESS VARCHAR2 (50)
CITY VARCHAR2 (25)
STATE VARCHAR2 (3)
You want to display details of all members who reside in states starting with the letter A followed by exactly one character.
Which SQL statement must you execute?
- A. SELECT * FROM MEMBERS WHERE state LIKE '%A_';
- B. SELECT * FROM MEMBERS WHERE state LIKE 'A_';
- C. SELECT * FROM MEMBERS WHERE state LIKE 'A%';
- D. SELECT * FROM MEMBERS WHERE state LIKE 'A_%';
Answer: B
NEW QUESTION 87
View the Exhibit and examine the data in the PROMOTIONS table.
PROMO_BEGIN_DATE is stored in the default date format, dd-mon-rr.
You need to produce a report that provides the name, cost, and start date of all promos in the POST category that were launched before January 1, 2000.
Which SQL statement would you use?
- A. SELECT promo_name, promo_cost, promo_begin_dateFROM promotionsWHERE promo_category =
'post' AND promo_begin_date < '01-01-00'; - B. SELECT promo_name, promo_cost, promo_begin_dateFROM promotionsWHERE promo_cost LIKE
'post%' AND promo_begin_date < '01-01-2000'; - C. SELECT promo_name, promo_cost, promo_begin_dateFROM promotionsWHERE promo_category LIKE 'P%' AND promo_begin_date < '1-JANUARY-00';
- D. SELECT promo_name, promo_cost, promo_begin_dateFROM promotionsWHERE promo_category LIKE '%post%' AND promo_begin_date < '1-JAN-00';
Answer: D
NEW QUESTION 88
You execute the SQL statement:
What is the outcome?
- A. It fails because the condition for the CNAMES constraint is not valid.
- B. It succeeds and an index is crated for CITIZEN_ID.
- C. It succeeds and CITY can contain only 'SEATTLE' or null for all rows.
- D. It fails because the NOT NULL and DEFAULT options cannot be combined for the same column.
Answer: D
NEW QUESTION 89
Which two statements are true about transactions in the Oracle Database server? (Choose two.)
- A. A session can always see uncommitted updates made by itself.
- B. An uncommitted transaction commits automatically if the user exists SQL*Plus.
- C. A user can always see uncommitted updates made by the same user in a different session.
- D. Data Manipulation Language (DML) statements always start a new transaction.
- E. If a session has an uncommitted transaction, then a DDL statement issues a COMMITbefore starting a new transaction.
- F. A Data Definition Language (DDL) statement does a COMMITautomatically only for the data dictionary updates caused by the DDL.
Answer: A,E
NEW QUESTION 90
Examine these SQL statements that are executed in the given order:
What will be the status of the foreign key EMP_MGR_FK?
- A. It will be enabled and immediate.
- B. It will be enabled and deferred.
- C. It will remain disabled and can be enabled only by dropping the foreign key constraint and re-creating it.
- D. It will remain disabled and can be re-enabled manually.
Answer: D
NEW QUESTION 91
Examine the data in the EMP table:
You execute this query:
SELECT deptno AS "Department", AVG(sal) AS AverageSalary, MAX(sal) AS "Max Salary"
FROM emp
WHERE sal >= 12000
GROUP BY "Department "
ORDER BY AverageSalary;
Why does an error occur?
- A. An alias name must not be used in a GROUP BY clause.
- B. An alias name must not be used in an ORDER BY clause.
- C. An allas name must not contain space characters.
- D. An alias name must always be specified in quotes.
Answer: A
NEW QUESTION 92
View and Exhibit and examine the structure and data in the INVOICE table. (Choose two.)
Which two statements are true regarding data type conversion in query expressions?
- A. inv_date = '15-february-2008' :uses implicit conversion
- B. CONCAT(inv_amt, inv_date) : requires explicit conversion
- C. inv_no BETWEEN '101' AND '110' : uses implicit conversion
- D. inv_amt = '0255982' : requires explicit conversion
- E. inv_date > '01-02-2008' : uses implicit conversion
Answer: A,C
NEW QUESTION 93
Examine the structure of the EMPLOYEES table.
There is a parent-child relationship between EMPLOYEE_ID and MANAGER_ID.
You want to display the last names and manager IDs of employees who work for the same manager as the employee whose EMPLOYEE_ID is 123.
Which query provides the correct output?
- A. SELECT e.last_name, e.manager_idFROM employees e RIGHT OUTER JOIN employees mon (e.employee_id = m.employee_id)WHERE e.employee_id = 123;
- B. SELECT e.last_name, m.manager_idFROM employees e LEFT OUTER JOIN employees mon (e.employee_id = m.manager_id)WHERE e.employee_id = 123;
- C. SELECT m.last_name, e.manager_idFROM employees e LEFT OUTER JOIN employees mon (e.manager_id = m.manager_id)WHERE e.employee_id = 123;
- D. SELECT e.last_name, m.manager_idFROM employees e RIGHT OUTER JOIN employees mon (e.manager_id = m.employee_id)AND e.employee_id = 123;
Answer: C
NEW QUESTION 94
Examine this query and its output:
Examine this query with an incomplete was WHERE clause:
Which two are true about operators that can be used In the WHERE clause?
- A. Using not in or <> any will give the same result.
- B. Using not in or <> all will give the same result.
- C. Using in will display all the product names,
- D. Using <> any will display all the product names except the product named Fork.
- E. Using <> any will display all the product names.
Answer: B,D
NEW QUESTION 95
Examine the description of the EMPLOYEEStable:
Which query is valid?
- A. SELECT dept_id, join_date, SUM(salary) FROM employees GROUP BY dept_id;
- B. SELECT dept_id, join_date, SUM(salary) FROM employees GROUP BY dept_id,
join_date; - C. SELECT dept_id, MAX(AVG(salary)) FROM employees GROUP BY dept_id;
- D. SELECT dept_id, AVG(MAX(salary)) FROM employees GROUP BY dept_id;
Answer: A
NEW QUESTION 96
Examine the description of the EMPLOYEES table:
Which statement will fail?
- A. SELECT department_id, COUNT (*)
FROM employees
WHERE department_ id <> 90 AND COUNT(*) >= 3
GROUP BY department_id; - B. SELECT department_id, COUNT(*)
FROM employees
WHERE department_id <> 90 GROUP BY department_id
HAVING COUNT(*) >= 3; - C. SELECT department_id, COUNT (*)
FROM employees
HAVING department_ id <> 90 AND COUNT(*) >= 3
GROUP BY department_id; - D. SELECT department_id, COUNT(*)
FROM employees
WHERE department_id <> 90 HAVING COUNT(*) >= 3
GROUP BY department_id;
Answer: A
NEW QUESTION 97
You are designing the structure of a table in which two columns have the specifications:
COMPONENT_ID- must be able to contain a maximum of 12 alphanumeric characters and must uniquely identify the row EXECUTION_DATETIME- contains Century, Year, Month, Day, Hour, Minute, Second to the maximum precision and is used for calculations and comparisons between components.
Which two options define the data types that satisfy these requirements most efficiently? (Choose two.)
- A. The COMPONENT_IDmust be of VARCHAR2 data type.
- B. The COMPONENT_IDcolumn must be of CHAR data type.
- C. The EXECUTION_DATETIME must be of DATE data type.
- D. The EXECUTION_DATETIME must be of TIMESTAMP data type.
- E. The EXECUTION_DATETIME must be of INTERVAL DAY TO SECOND data type.
- F. The COMPONENT_IDmust be of ROWID data type.
Answer: B,C
Explanation:
Explanation
NEW QUESTION 98
Examine the structure of the EMPLOYEEStable.
There is a parent/child relationship between EMPLOYEE_IDand MANAGER_ID.
You want to display the last names and manager IDs of employees who work for the same manager as the employee whose EMPLOYEE_IDis 123.
Which query provides the correct output?
- A. SELECT e.last_name, m.manager_id
FROM employees e RIGHT OUTER JOIN employees m
on (e.manager_id = m.employee_id)
AND e.employee_id = 123; - B. SELECT m.last_name, e.manager_id
FROM employees e LEFT OUTER JOIN employees m
on (e.manager_id = m.manager_id)
WHERE e.employee_id = 123; - C. SELECT e.last_name, m.manager_id
FROM employees e LEFT OUTER JOIN employees m
on (e.employee_id = m.manager_id)
WHERE e.employee_id = 123; - D. SELECT e.last_name, e.manager_id
FROM employees e RIGHT OUTER JOIN employees m
on (e.employee_id = m.employee_id)
WHERE e.employee_id = 123;
Answer: B
NEW QUESTION 99
Examine the description of the ENPLYEES table:
Which two queries return all rows for employees whose salary is greater than the average salary in their department?
- A. SELECT"
FROM employees e1
WHERE salary >!
SELECT AVG (salary)
FROM employees e2
WHERE e1. Department _id = e2, department_ id - B. SELECT
FROM employees
WHERE salary > AVG (salary) OVER (PARTITION BY department _ id); - C. SELECT"
FROM employees
WHERE salary >
( SELECT AVG
(salary) FROM
employees
GROUP BY department _ id - D. SELECT.
FROM
SELECT e.", AVG (salary) OVER (PARTITION BY department id) avg_ sal
FROM employees e
WHERE salary > avg_ sal; - E. SELECT "
FROM employees
WHERE salary > ANY
SELECT AVG (salary)
EROM employees
GROUP BY department_ id);
Answer: A,D
NEW QUESTION 100
Examine the description of the CUSTOMERS table:
You need to display last names and credit limits of all customers whose last name starts with A or B In lower or upper case, and whose credit limit is below 1000.
Examine this partial query:
SELECT cust_last_nare, cust_credit_limit FROM customers
Which two WHERE conditions give the required result?
- A. WHERE (INITCAP(cust_last_name) LIKE 'A%' OR ITITCAP(cust_last_name) LIKE 'B%') AND cust_credit_limit < 1000
- B. WHERE UPPER(cust_last_name) BETWEEN UPPER('A%' AND 'B%') AND ROUND(cust_credit_limit) < 1000;
- C. WHERE UPPER(cust_last_name) IN ('A%', 'B%') AND cust_credit_limit < 1000:
- D. WHERE (UPPER(cust_last_name) LIKE 'A%' OR UPPER(cust_last_name) LIKE 'B%') AND ROUND(cust_credit_limit) < 1000;
- E. WHERE (UPPER(cust_last_name) like INITCAP ('A') OR UPPER(cust_last_name) like INITCAP('B')) AND ROUND(cust_credit_limit) < ROUND(1000) ;
Answer: A,D
NEW QUESTION 101
In the customers table, the CUST_CITY column contains the value 'Paris' for the CUST_FIRST_NAME 'Abigail'.
Evaluate the following query:
What would be the outcome?
- A. Abigail IS
- B. Abigail Pa
- C. An error message
- D. Abigail PA
Answer: B
NEW QUESTION 102
View the Exhibit and examine the structure of the ORDERS table.
Which UPDATE statement is valid?
- A. UPDATE ordersSET order_date = '12-mar-2007',AND order_total = TO_NUMBER(NULL)WHERE order_id = 2455;
- B. UPDATE ordersSET order_date = '12-mar-2007',order_total = NULLWHERE order_id = 2455;
- C. UPDATE ordersSET order_date = TO_DATE('12-mar-2007','dd-mon-yyyy'),SET order_total = TO_NUMBER (NULL)WHERE order_id = 2455;
- D. UPDATE ordersSET order_date = '12-mar-2007',order_total IS NULLWHERE order_id = 2455;
Answer: B
NEW QUESTION 103
Which two statements are true about date/time functions in a session where NLS_DATE_PORMAT is set to DD-MON-YYYY SH24:MI:SS
- A. CURRENT_TIMESTAMP returns the same date as CURRENT_DATE.
- B. CURRENT_TIMESTAMP returns the same date and time as SYSDATE with additional details of functional seconds.
- C. CURRENT_DATE returns the current date and time as per the session time zone
- D. SYSDATE can be used in expressions only if the default date format is DD-MON-RR.
- E. SYSDATE and CURRENT_DATE return the current date and time set for the operating system of the database server.
- F. SYSDATE can be queried only from the DUAL table.
Answer: B,C
NEW QUESTION 104
Which two are true about the USING clause when joining tables?
- A. It can never be used with a full outer join.
- B. It can never be used with onatural join.
- C. All column names in a USING clause must be qualified with a table name or table alias.
- D. It is used to specify an equijoin of columns that have the same name in both tables.
- E. It is used to specify an explicit join condition involving operators.
Answer: B,E
NEW QUESTION 105
Examine the structure of the MEMBERStable.
Which query can be used to display the last names and city names only for members from the states MO and MI?
SELECT last_name, city FROM members WHERE state ='MO' AND state ='MI';
- A. SELECT DISTINCT last_name, city FROM members WHERE state ='MO' OR state ='MI';
- B. SELECT last_name, city FROM members WHERE state IN ('MO', 'MI');
- C. SELECT last_name, city FROM members WHERE state LIKE 'M%';
- D.
Answer: A
NEW QUESTION 106
Examine this SQL statement:
Which two are true?
- A. The subquery is executed for every row in the employees table.
- B. The subquery is not a correlated subquery.
- C. All existing rows in the EMPLOYEES table are deleted.
- D. The DELETE statement executes successfully even if the subquery selects multiple rows.
- E. The subquery is executed before the DELETE statement is executed.
Answer: A,E
NEW QUESTION 107
View the Exhibits and examine PRODUCTS and SALES tables.
Exhibit 1
Exhibit 2
You issue the following query to display product name the number of times the product has been sold:
What happens when the above statement is executed?
- A. The statement executes successfully and produces the required output.
- B. The statement produces an error because a subquery in the FROM clause and outer-joins cannot be used together.
- C. The statement produces an error because ITEM_CNT cannot be displayed in the outer query.
- D. The statement produces an error because the GROUP BY clause cannot be used in a subquery in the FROM clause.
Answer: A
NEW QUESTION 108
......
Introduction to Oracle 1Z0-071: Oracle Database SQL Exam
The Oracle Database SQL Management exam evaluates the knowledge and skills of RAC and Grid Infrastructure Database Administrators and System Administrators with at least one year of experience. Candidates should be able to mount, maintain, monitor, tune and restore RAC databases, clusters and Oracle Automated Storage Management (ASM). You should have a clear knowledge of ASM, Clusterware and Oracle RAC database architectures. They should also be able to track and tune the upload, configuration, backup, and retrieval of these components.
For Oracle Data Base Software produced by Oracle Corporation, the Oracle Real Application Cluster (RAC) in data base computing offers clustering software and high availability in Oracle database environments. Oracle Corporate provides RAC in the Business version, provided that the nodes are clustered using Oracle Clusterware. Oracle RAC requires many computers to operate Oracle RDBMS applications concurrently with clustering while accessing a single database.
Oracle Grid Infrastructure is the software Oracle that maintains a storage framework that involves file system control, volume management and restart process automation. You need to set up Oracle grid infrastructure before deploying Oracle Database if you want to use Oracle restart or Oracle Automated Storage Management (ASM) services.
Tested Material Used To 1z1-071 Test Engine: https://www.prep4sureguide.com/1z1-071-prep4sure-exam-guide.html
Steps Necessary To Pass The 1z1-071 Exam: https://drive.google.com/open?id=1cuiax2fNpsL1P6iJKh7tA5O27XwrX7fq