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Oracle Introduction to Oracle9i: SQL Sample Questions:

1. Which syntax turns an existing constraint on?

A) ALTER TABLE table_name
ENABLE constraint_name;
B) ALTER TABLE table_name
ENABLE CONSTRAINT constraint_name;
C) ALTER TABLE table_name
STATUS ENABLE CONSTRAINT constraint_name;
D) ALTER TABLE table_name
TURN ON CONSTRAINT constraint_name;
E) ALTER TABLE table_name
STATUS = ENABLE CONSTRAINT constraint_name;
F) ALTER TABLE table_name
TURN ON CONSTRAINT constraint_name;

2. What is true about joining tables through an equijoin?

A) To join two tables through an equijoin, the columns in the join condition must be primary key and foreign key columns.
B) You specify an equijoin condition in the SELECT or FROM clauses of a SELECT statement.
C) You can join a maximum of two tables through an equijoin.
D) You can join a maximum of two columns through an equijoin.
E) You can join n tables (all having single column primary keys) in a SQL statement by specifying a minimum of n-1 join conditions.

3. The STUDENT_GRADES table has these columns:

The registrar has asked for a report on the average grade point average (GPA) for students enrolled during semesters that end in the year 2000. Which statement accomplish this?

A) SELECT SUM (gpa)
FROM student grades
WHERE semester_end > '01-JAN-2000' and semester end < '31-DEC-2000';
B) SELECT MEDIAN (gpa)
FROM student_grades
WHERE semester end > '01-JAN-2000' and semester end < '31-DEC-2000';
C) SELECT MIN (gpa)
FROM student grades
WHERE semester_end > '01-JAN-2000' and semester end < '31-DEC-2000';
D) SELECT AVERAGE (gpa)
FROM student_grades
WHERE semester_end > '01-JAN-2000' and semester end < 31-DEC-2000';
E) SELECT AVG (gpa)
FROM student_grades
WHERE semester_end BETWEEN '01-JAN-2000' and '31.DEC.2000';
F) SELECT COUNT (gpa)
FROM student grades
WHERE semester_end > '01-JAN-2000' and semester end < '31-DEC-2000';

4. You need to write a SQL statement that returns employee name, salary, department ID, and maximum salary earned in the department of the employee for all employees who earn less than the maximum salary in their department.
Which statement accomplishes this task?

A) SELECT a.emp_name, a.sal, a.dept_id, b.maxsal FROM employees a WHERE a.sal < (SELECT MAX(sal) maxsal FROM employees b GROUP BY dept_id);
B) SELECT emp_name, sal, dept_id, maxsal FROM employees, (SELECT dept_id, MAX(sal) maxsal FROM employees GROUP BY dept_id) WHERE a.sal < maxsal;
C) SELECT a.emp_name, a.sal, a.dept_id, b.maxsal FROM employees a, (SELECT dept_id, MAX(sal) maxsal FROM employees GROUP BY dept_id) b WHERE a.dept_id = b.dept_id AND a.sal < b.maxsal;
D) SELECT a.emp_name, a.sal, b.dept_id, MAX(sal) FROM employees a, departments b WHERE a.dept_id = b.dept_id AND a.sal < MAX(sal) GROUP BY b.dept_id;

5. Examine the structure of the EMPLOYEES table:

You need to create an index called NAME_IDX on the first name and last name fields of the EMPLOYEES table. Which SQL statement would you use to perform this task?

A) CREATE INDEX NAME_IDX
FOR employees(first_name, last_name);
B) CREATE INDEX NAME_IDX (first_name, last_name);
C) CREATE INDEX NAME_IDX
ON (first_name, last_name);
D) CREATE INDEX NAME_IDX
ON employees (first_name AND last_name);
E) CREATE INDEX NAME_IDX
ON employees(first_name, last_name);
F) CREATE INDEX NAME_IDX (first_name AND last_name);

Solutions: